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A shipping container in the shape of a right rectangular prism has a length of 16 feet, a width of 8 feet, and a height of 4.5 feet. The container is completely filled with contents that weigh, on average, 0.50 pound per cubic foot. What is the weight, in pounds, of the contents in the container?

Respuesta :

calculista

Answer:

The weight of the contents in the container is [tex]288\ lb[/tex]

Step-by-step explanation:

step 1

Find the volume of the container

The volume is equal to

[tex]V=LWH[/tex]

substitute the values

[tex]V=(16)(8)(4.5)=576\ ft^{3}[/tex]

step 2

Multiply the volume of the container by [tex]0.50\frac{lb}{ft^{3}}[/tex] to obtain the weight of the contents in the container

[tex]576(0.50)=288\ lb[/tex]

faderh235

Answer:

=121 lbs

Step-by-step explanation:

V=

V=

\,\,l \cdot w \cdot h

l⋅w⋅h

Volume of a Rectangular Prism

V=

V=

\,\,(4.5 )( 5 )( 5.5)

(4.5)(5)(5.5)

V=

V=

\,\,123.75\text{ }\text{ft}^3

123.75 ft

3

123.75\text{ }\text{ft}^3 \cdot\frac{0.98\text{ }\text{lbs}}{\text{ft}^3}=121\text{ }\text{lbs}

123.75 ft

3

⋅

ft

3

0.98 lbs

​

=121 lbs

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