Answer:
The area of a sector MVP is [tex]14\pi \ m^{2}[/tex]
Step-by-step explanation:
step 1
Find the area of the circle
The area of the circle is equal to
[tex]A=\pi r^{2}[/tex]
we have
[tex]r=6\ m[/tex]
substitute
[tex]A=\pi (6)^{2}=36 \pi\ m^{2}[/tex]
step 2
we know that
The area of the complete circle subtends a central angle of 360 degrees
so
by proportion
Find the area of a sector for a central angle of 140 degrees
[tex]\frac{36 \pi}{360} =\frac{x}{140}\\ \\x=36\pi *140/360\\ \\x=14\pi \ m^{2}[/tex]
