What is the solution set of the quadratic inequality 6x^2+1 greater than or equal to 0?
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Answer:
C
Step-by-step explanation:
6x^2 + 1 <= 0
6x^2 <= -1
x^2 <= -1/6
Since we cannot take the square root of a negative number, there is no solution.
The solution set of the quadratic inequality [tex]6x^2+1 \leq 0[/tex] is empty (∅).
Inequality is a statement of an order relationship "greater than, greater than or equal to, less than, or less than or equal to" between two numbers or algebraic expressions.
The equation whose highest degree of the variable is 2, then it is said to be a quadratic equation.
Given quadratic inequality as [tex]6x^2+1 \leq 0[/tex]
Adding -1 on both sides (subtracting 1)
[tex]6x^2+1 -1 \leq 0 -1[/tex]
⇒ [tex]6x^2\leq -1[/tex]
Dividing with 6 both sides
⇒ [tex]x^2\leq \frac{-1}{6}[/tex]
Since the value is negative and the root for negative numbers is not defined, the given inequality has no solution.
Therefore, the solution set for the quadratic inequality [tex]6x^2+1 \leq 0[/tex] is an empty set (∅).
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