Answer:
The measure of the smaller arc is [tex]36\°[/tex]
Step-by-step explanation:
we know that
The measurement of the external angle is the semi-difference of the arcs which comprises
Let
x-----> the measure of the bigger arc
y----> the measure of the smaller arc
we know that
[tex]32\°=\frac{1}{2}(arc\ x-arc\ y)[/tex]
we have
[tex]arc\ x=100\°[/tex]
substitute the values and solve for arc y
[tex]32\°=\frac{1}{2}(100\°-arc\ y)[/tex]
[tex]64\°=(100\°-arc\ y)[/tex]
[tex]arc\ y=100\°-64\°=36\°[/tex]