Answer:
Percent of Robbery [tex]=2 \%[/tex]
Percent of Robbery [tex]=9 \%[/tex]
Step-by-step explanation:
Given that total number of crimes = 21,790,654.
total number of Robbery = 408, 016 and
total number of Burglary = 2,050,992
Now we need to find about what are their percent in crimes rounded to the nearest percent for each two crimes.
So apply the percent formula
[tex]Percent=\frac{Part}{Whole}\times 100 \%[/tex]
Then percent of Robbery [tex]=\frac{408016}{21790654}\times 100 \%=0.01872\times 100 \%=2 \%[/tex]
Then percent of Robbery [tex]=\frac{2050992}{21790654}\times 100 \%=0.094122\times 100 \%=9 \%[/tex]
