Factor completely. 12x4+18x3+45x2 Enter your answer in the box.

What are the roots of the polynomial equation?

x2+6x−72=0

Enter your answers in the boxes.

x=
or x=

Boris solves the system of equations using the linear combination method.

3x+4y=−87x−3y=6

Which steps would allow him to eliminate the y terms in the system of equations?

Multiply 3x+4y=−8

by 7. Multiply 7x−3y=6 by −3
. Add the resulting equations together.
Multiply 3x+4y=−8
by 4. Multiply 7x−3y=6
by 3. Add the resulting equations together.
Multiply 3x+4y=−8
by −3 . Multiply 7x−3y=6
by 7. Add the resulting equations together.
Multiply 3x+4y=−8
by 3. Multiply 7x−3y=6 by 4. Add the resulting equations together.

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kudzordzifrancis kudzordzifrancis · Answer 1 · 2019-04-21T05:14:26+02:00

QUESTION 1

The given expression is

[tex]12x^4+18x^3+45x^2[/tex]

The greatest common factor is [tex]3x^2[/tex].

We factor to obtain;

[tex]3x^2(4x^2+6x+15)[/tex]

QUESTION 2

The given quadratic equation is

[tex]x^2+6x-72=0[/tex]

We split the middle term to obtain

[tex]x^2+12x-6x-72=0[/tex]

Factor by grouping;

[tex]x(x+12)-6(x+12)=0[/tex]

[tex](x+12)(x-6)=0[/tex]

Use zero product property;

[tex](x+12)=0\:\:or\:\:(x-6)=0[/tex]

[tex]x=-12\:\:or\:\:x=6[/tex]

QUESTION 3

The given system of equation is

[tex]3x+4y=-8[/tex]

[tex]7x-3y=6[/tex]

If we multiply [tex]3x+4y=-8[/tex] by 3, we obtain;

[tex]9x+12y=-24[/tex]

If we multiply [tex]7x-3y=6[/tex] by 4 we obtain;

[tex]28x-12y=24[/tex]

Adding the last two equations will give us;

[tex]37x=0[/tex]

The y-variable is eliminated.

Answer:Multiply 3x+4y=−8

by 3. Multiply 7x−3y=6 by 4. Add the resulting equations together.