Answer: The initial height of the ball is 12 feet.
Step-by-step explanation:
We have the function [tex]h(t)=-16t^2+26t+12[/tex], which models the height (in feet) of the ball after [tex]t[/tex] seconds.
Then, as the height is in function of the time, we know that the ball is in the initial height when:
[tex]t=0[/tex]
So, to find the initial height, you need to substitute [tex]t=0[/tex] into the function:
[tex]h(0)=-16(0)^2+26(0)+12\\\\h(0)=0+0+12\\\\h(0)=12[/tex]
Therefore, the initial height of the ball is 12 feet.
