For this case we have:
Let y the variable that represents the number of miles Samantha walks according to school days (represented by varibale x)
So:
[tex]y = \frac {2} {3} x[/tex]
If we have that samantha walks 5 days, then we substitute[tex]x = 5[/tex].
[tex]y = \frac {2} {3} (5)\\y = \frac {10} {3}[/tex]
So, Samantha walks \[tex]\frac {10} {3}[/tex]miles for 5 days, to go to and from school.
Answer:
[tex]\frac {10} {3}[/tex]
