Plz help me with this

Answer: [tex]\bold{b)\quad \dfrac{-\sqrt{13}-5}{4}}[/tex]
Step-by-step explanation:
[tex]\dfrac{3}{\sqrt{13}-5}\bigg(\dfrac{\sqrt{13}+5}{\sqrt{13}+5}\bigg)\\\\\\=\dfrac{3(\sqrt{13}+5)}{13-25}\\\\\\=\dfrac{3(\sqrt{13}+5)}{-12}\\\\\\=\dfrac{\sqrt{13}+5}{-4}\\\\\\=\dfrac{-\sqrt{13}-5}{4}[/tex]