Respuesta :

Answer: Option C

Step-by-step explanation:

The solution from the number line is  (-∞,-3]∪[1,∞)

Given equation :

[tex]|x+b| ---2[/tex]

[tex](x+b) ----2[/tex] or

[tex]-(x+b)---2[/tex]

Putting b=1 and the inequality ≥ gives the required solution.

[tex]|x+1|\geq 2[/tex]

=> [tex](x+1)\geq 2[/tex] or [tex]-(x+1)\geq 2[/tex]

=> [tex]x\leq -3[/tex] or [tex]x\geq 1[/tex]

raphealnwobi

The inequality solved to give a solution of x ≥ 1 and x ≤ -3 is |x + 1| ≥ 2. b = 1, ≥

What is an inequality?

An inequality is an expression that shows the non equal comparison between two or more variables and numbers.

From the diagram, the solution to the inequality is x ≥ 1 and x ≤ -3

Hence:

|x + b| ≥ 2

x + b ≥ 2 or -(x + b) ≥ 2

x ≥ 2 - b or x ≤ -2 - b

2 - b = 1 and -2 - b = -3

b = 1

Hence |x + 1| ≥ 2

The inequality solved to give a solution of x ≥ 1 and x ≤ -3 is |x + 1| ≥ 2. b = 1, ≥

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