Respuesta :
Answer:
The approximate height of the paint can is 8.2 in
Step-by-step explanation:
we know that
The volume of the cylinder ( can of paint) is equal to
[tex]V=\pi r^{2} h[/tex]
we have
[tex]V=231\ in^{3}[/tex]
[tex]r=3\ in[/tex]
[tex]\pi=3.14[/tex]
Substitute the values and solve for h
231=(3.14)(3)^{2} h
h=231/(3.14*9)=8.2 in