Need help with finding the area of this prism

Answer:
[tex]\large\boxed{S.A.=116\ cm^2}[/tex]
Step-by-step explanation:
Look at the picture.
Use the Pythagorean theorem:
[tex]x^2+3^2=5^2[/tex]
[tex]x^2+9=25[/tex] subtract 9 from both sides
[tex]x^2=16\to x=\sqrt{16}\\\\x=4[/tex]
The Surface Area:
we have two congruent right triangles and three rectangles
The area of a right triangle:
[tex]A_T=\dfrac{(3)(4)}{2}=6\ cm^2[/tex]
The areas of the rectangles:
[tex]A_{R1}=(5)(7)=35\ cm^2\\\\A_{R2}=(3)(7)=21\ cm^2\\\\A_{R3}=(4)(7)=28\ cm^2[/tex]
The Surface Area:
[tex]S.A.=2A_T+A_{R1}+A_{R2}+A_{R3}\\\\S.A.=2\cdot6+35+21+48=116\ cm^2[/tex]
Answer:
Surface area = 96 cm²
Step-by-step explanation:
From the figure we can see that, a prism
To find the height of triangles
Height²= Hypotenuse² - Base 2 = 5² - 3² = 16
Height = 4
To find the surface area
Surface area = Area of two triangles + Area of 2 side face + Area of base
Area of triangles
Area = bh/2 = (3 * 4)/2 = 6 cm²
Area of 2 triangles = 2 * 6 = 12 cm²
Area of side face
Area first face = 7 * 3 = 21 cm ²
Area of second face = 7 * 4 = 28 cm ²
Total area of side face = 21 + 28 = 49 cm²
Area of base
Area of base = 7 * 5 = 35 cm²
Total surface area = 12 + 49 + 35 = 96 cm²