BC is tangent to circle A at point B. What is m2ACB if mZCAB = 22° ?
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Answer:
68°
Step-by-step explanation:
We know that sum of 3 angles in a triangle is 180°.
In ΔBAC, there are angles B, A, and C. Thus we can say:
B + A + C = 180
Since, BC is tangent to circle, the point of tangency, B is a 90 degree angle. So angle B is 90.
Also, given angle CAB is 22, which, in other word, is angle A is 22.
Thus, we can write:
B + A + C = 180
90 + 22 + C = 180
112 + C = 180
C = 180 - 112 = 68
Measure of angle ACB = 68°