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Find the magnitude of the sum
of these two vectors:
12.0 m
45.0° 9.66 m

please HELP me with this ​

Find the magnitude of the sumof these two vectors120 m 450 966 m please HELP me with this class=

Respuesta :

Answer:

8.57 m

Explanation:

To solve the problem, we have to decompose the two vectors along the two directions first:

Vector A:

- x component: Ax = +9.66 m

- y compoment: Ay = 0 (the vector lies along the x-axis)

Vector B:

- x component: [tex]B_x = -(12.0 m) cos 45^{\circ}=-8.49 m[/tex]

- y component: [tex]B_y = (12.0 m) sin 45^{\circ}=8.49 m[/tex]

So now we can find the sum of the two vectors by adding the components along each axis:

[tex]R_x = A_x + B_x = 9.66 m - 8.49 m = 1.17 m[/tex]

[tex]R_y = A_y + B_y = 0 + 8.49 m = 8.49 m[/tex]

And the magnitude of the sum is given by Pythagorean theorem:

[tex]R=\sqrt{R_x^2+R_y^2}=\sqrt{(1.17 m)^2+(8.49 m)^2}=8.57 m[/tex]