Respuesta :

Answer:

Final answer is [tex]\frac{3x^2+6x}{x^2-16}[/tex].

Step-by-step explanation:

Given rational expressions are [tex]\frac{x+2}{x-4}[/tex] and [tex]\frac{3x}{x+4}[/tex].

Now we need to find about what is the product of given rational expressions.

to multiply the rational expressions, we simply multiply numerator with numerator. Then multiply denominator with denominator.

[tex]\frac{x+2}{x-4}\cdot\frac{3x}{x+4}[/tex]

[tex]=\frac{\left(x+2\right)\cdot3x}{\left(x-4\right)\cdot\left(x+4\right)}[/tex]

[tex]=\frac{3x^2+6x}{x^2+4x-4x-16}[/tex]

[tex]=\frac{3x^2+6x}{x^2-16}[/tex]

Hence final answer is [tex]\frac{3x^2+6x}{x^2-16}[/tex].

Answer:

definitely 3x^2+6x/x^2-16

Step-by-step explanation:

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