Answer with explanation:
[tex]\text{Average}=\frac{\text{Sum of all the observation}}{\text{Total number of Observation}}[/tex]
Average Height of tallest Building in San Francisco
[tex]=\frac{260+237+212+197+184+183+183+175+174+173}{10}\\\\=\frac{1978}{10}\\\\=197.8[/tex]
Average Height of tallest Building in Los Angeles
[tex]=\frac{310+262+229+228+224+221+220+219+213+213}{10}\\\\=\frac{2339}{10}\\\\=233.9[/tex]
→→Difference between Height of tallest Building in Los Angeles and Height of tallest Building in San Francisco
=233.9-197.8
=36.1
⇒The average height of the 10 tallest buildings in Los Angeles is 36.1 more than the average height of the tallest buildings in San Francisco.
⇒Part B
Mean absolute deviation for the 10 tallest buildings in San Francisco
|260-197.8|=62.2
|237-197.8|=39.2
|212-197.8|=14.2
|197 -197.8|= 0.8
|184 -197.8|=13.8
|183-197.8|=14.8
|183-197.8|= 14.8
|175-197.8|=22.8
|174-197.8|=23.8
|173 -197.8|=24.8
Average of these numbers
[tex]=\frac{62.2+39.2+14.2+0.8+13.8+14.8+14.8+22.8+23.8+24.8}{10}\\\\=\frac{231.2}{10}\\\\=23.12[/tex]
Mean absolute deviation=23.12
