Answer:
[tex]\boxed{\text{3,3-dimethyl-1-pentene}}[/tex]
Explanation:
1. Identify and name the longest continuous chain of carbon atoms ( in red: pentane).
2. Replace the -ane ending of the alkane with -ene to get the base name pentene.
3. Number the carbon atoms from the end closest to the double bond.
4. Locate the double bond by using the lower-numbered of its two carbon atoms. Insert the number of the locant just before the -ene. Use a hyphen to connect numbers and letters. The parent name is pent-1-ene.
5. Locate and name the substituents.
There are two one-carbon sidechains (blue bonds: methyl groups) on C3.
Each substituent receives its own number: 3-methyl. Numbers are connected to letters by hyphens
Use a multiplying prefix to indicate the number of methyl groups (dimethyl) and connect numbers to numbers by commas (3,3-dimethyl).
6. Attach the names of the substituents to the front of the parent name.
The correct IUPAC name is 3,3-dimethylpent-1-ene.
Note: The name [tex]\boxed{\text{3,3-dimethyl-1-pentene}}[/tex] is acceptable, but the Preferred IUPAC Name puts the locants as close as possible in front of the groups they locate.
