Answer:
[tex]\frac{\sqrt{11} }{6}[/tex]
Step-by-step explanation:
Using the Pythagorean identity
sin²x + cos²x = 1, then
cosx = [tex]\sqrt{1-sin^2x}[/tex]
cosΘ = [tex]\sqrt{1-(5/6)^2}[/tex]
= [tex]\sqrt{1-\frac{25}{36} }[/tex] = [tex]\sqrt{\frac{11}{36} }[/tex] = [tex]\frac{\sqrt{11} }{6}[/tex]
