A small planet having a radius of 1000 km exerts a gravitational force of 100 N on an object that is 500 km above its surface. If this object is moved 500 km farther from the planet, the gravitational force on it will be closest to :(A) 75 N(B) 71 N(C) 56 N(D) 50 N(E) 25 N

Respuesta :

Answer:

56 N

Explanation:

Gravitational force on the object:

[tex]F = G\frac{Mm}{d^2}[/tex]

where, G is the gravitational constant, M is the mass of the planet and m is the mass of the object, d is the distance between the planet and the object.

[tex]F \times d^2= GMm\\ \Rightarrow GMm= (100)(1.5\times10^6)^2[/tex]

d'=d+500 km

[tex]F'=\frac{(100)(1.5\times10^6)^2}{(2\times10^6)^2} = 56.25N[/tex]

Thus, option (c) is correct.