Answer:
Explanation:
The total energy required to convert 1 mole of liquid from 5°C below its boiling point to 1 mole of gaseous Ar at 5° above its boiling point may be calcualted in three stages:
- Heating the liquid Ar from 5°C below its boling point to the boiling point
- Vaporizing the liquid Ar at its boiling temperature
- Heating the gaseous Ar from its boiling point to 5°C above it.
1) Energy to heat the liquid Ar from 5°C below its boling point to the boiling point:
- Q₁ = m × C × ΔT = 1 mol × 25.0 J/mol°C × 5°C = 125 J
2) Energy to vaporize the liquid Ar:
- Q₂ = m × Latent heat of vaporization = 1 mol × 6506 J/mol = 6506 J
3) Energy to heat the gaseous Ar 5°C above its boiling point:
- Q₃ = m × C × ΔT = 1 mol × 20.8 J/mol°C × 5°C = 104 J
4) Total energy (E)
- E = Q₁ + Q₂ + Q₃ = 125 J + 6506 J + 104 J = 6735 J ← answer
