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find three consecutive positive even integers such that the product of the second and third integers is 20 more than 10 times the first integer.

find three consecutive positive even integers such that the product of the second and third integers is 20 more than 10 times the first integer class=

Respuesta :

ImKC

Answer: 6, 8, 10

Step-by-step explanation:

We can write the three numbers as: x, x+2, and x+4

(x+2)(x+4) = 10x + 20

x² + 6x + 8 = 10x + 20

x² - 4x - 12 = 0

(x-6)(x+2) = 0

x = -2,6

We will focus on x = 6 and ignore -2

To check our answer: (6+2)(6+4) = 10(6) + 20?

                                     8*10 = 60 + 20?

                              Yes, 80 = 80

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