Answer:
6.4 N
Explanation:
Draw free body diagrams for each mass.
For the mass on the inclined surface, the sum of forces parallel to the incline are:
∑F = ma
T - Mg sin θ = Ma
For the hanging mass, the sum of the forces in the y direction are:
∑F = ma
T - mg + F = m(-a)
We're given that g = 9.8 m/s², M = 11 kg, m = 2.1 kg, F = 6.6 N, and a = 3.6 m/s².
From the second equation, we have everything we need to find the tension force.
T - (2.1)(9.8) + 6.6 = (2.1)(-3.6)
T = 6.42 N
Rounded to 2 sig figs, the tension is 6.4 N.
