Respuesta :
The oxidation number of each element in the compound are:
1. The oxidation number of K is +1
2. The oxidation number of O is –2
3. The oxidation number of Mn is +7
The oxidation number of certain elements are constant while others varies.
- The oxidation number of potassium, K is always +1
- The oxidation number of oxygen, O is always –2 except in peroxides where it is –1
- Manganese, Mn has variable oxidation number. Thus, we shall determine the oxidation number of Mn in the compound
The oxidation number of Mn in KMnO₄ can be obtained as follow:
KMnO₄ = 0 (ground state)
K = +1
O = –2
Mn = ?
KMnO₄ = 0
K + Mn + 4O = 0
1 + Mn + 4(–2) = 0
1 + Mn – 8 = 0
Collect like terms
Mn = 0 + 8 – 1
Mn = +7
Therefore, the oxidation number of Mn in KMnO₄ is +7
SUMMARY
1. The oxidation number of K is +1
2. The oxidation number of O is –2
3. The oxidation number of Mn is +7
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