Answer:
Yes
Explanation:
The velocity measured by Jennifer and Johnny is
[tex]v_m = 34.87 m/s[/tex]
The actual velocity is
[tex]v=34.15 m/s[/tex]
We can calculate the % error of the students measurement as follows:
[tex]Err = \frac{v_m - v}{v}\cdot 100 = \frac{34.87 m/s-34.15 m/s}{34.15 m/s}\cdot 100 =0.021 \cdot 100 = 2.1 \%[/tex]
Which is lower than the 2.5% maximum error required, so the two students will pass the test.