Answer:
Option A. 20.0 square units
Step-by-step explanation:
Let
[tex]A(2, 5),B(-4, 3),C(-3, 0),D(3, 2)[/tex]
Plot the points
see the attached figure
The area of the rectangle is equal to
[tex]A=AB*AD[/tex]
the formula to calculate the distance between two points is equal to
[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]
step 1
Find the distance AB
[tex]A(2, 5),B(-4, 3)[/tex]
substitute in the formula
[tex]AB=\sqrt{(3-5)^{2}+(-4-2)^{2}}[/tex]
[tex]AB=\sqrt{(-2)^{2}+(-6)^{2}}[/tex]
[tex]AB=\sqrt{40}\ units[/tex]
step 2
Find the distance AD
[tex]A(2, 5),D(3, 2)[/tex]
substitute in the formula
[tex]AD=\sqrt{(2-5)^{2}+(3-2)^{2}}[/tex]
[tex]AD=\sqrt{(-3)^{2}+(1)^{2}}[/tex]
[tex]AD=\sqrt{10}\ units[/tex]
step 3
Find the area of rectangle
[tex]A=AB*AD[/tex]
we have
[tex]AB=\sqrt{40}\ units[/tex]
[tex]AD=\sqrt{10}\ units[/tex]
substitute
[tex]A=(\sqrt{40})*(\sqrt{10})[/tex]
[tex]A=20\ units^{2}[/tex]
