Answer:
[tex]\frac{a^3b^2}{a^{-1}b^{-3}}=a^{4}b^{5}[/tex]
Step-by-step explanation:
Given : Expression [tex]\frac{a^3b^2}{a^{-1}b^{-3}}[/tex]
To find : Multiply or divide as indicated. Leave your answer with no factors in the denominator.
Solution :
We know when two same term are in divide then their power get subtracted.
So, [tex]\frac{a^m}{a^n}=a^{m-n}[/tex]
Applying in the expression,
[tex]\frac{a^3b^2}{a^{-1}b^{-3}}=a^{3-(-1)}b^{2-(-3)}[/tex]
Solve the power,
[tex]\frac{a^3b^2}{a^{-1}b^{-3}}=a^{3+1}b^{2+3}[/tex]
[tex]\frac{a^3b^2}{a^{-1}b^{-3}}=a^{4}b^{5}[/tex]
Therefore, The solution is [tex]\frac{a^3b^2}{a^{-1}b^{-3}}=a^{4}b^{5}[/tex]
