Respuesta :
For this case we propose a system of equations:
x: Variable representing the weight of large boxes
y: Variable that represents the weight of the small boxes
So
[tex]x + y = 80\\55x + 70y = 4850[/tex]
We clear x from the first equation:
[tex]x = 80-y[/tex]
We substitute in the second equation:
[tex]55 (80-y) + 70y = 4850\\4400-55y + 70y = 4850\\15y = 450\\y = 30[/tex]
We look for the value of x:
[tex]x = 80-30\\x = 50[/tex]
Large boxes weigh 50 pounds and small boxes weigh 30 pounds
Answer:
Large boxes weigh 50 pounds and small boxes weigh 30 pounds
Answer: A large box weighs 50 pounds and a small box weighs 30 pounds.
Step-by-step explanation:
Set up a system of equations.
Let be "l" the weight of a large box and "s" the weight of a small box.
Then:
[tex]\left \{ {{l+s=80} \atop {55l+70s=4,850}} \right.[/tex]
You can use the Elimination method. Multiply the first equation by -55, then add both equations and solve for "s":
[tex]\left \{ {{-55l-55s=-4,400} \atop {55l+70s=4,850}} \right.\\.............................\\15s=450\\\\s=\frac{450}{15}\\\\s=30[/tex]
Substitute [tex]s=30[/tex] into an original equation and solve for "l":
[tex]l+(30)=80\\\\l=80-30\\\\l=50[/tex]