Answer:
Explanation:
1) In a sublevel for which l = 0, there are _1__ orbital(s), and the maximum number of electrons that can be accommodated is _2__.
l represents the azimuthal quantum numbers and l = n-1. Where n is the principal quantum number. The principal quantum number(n) gives the main energy level in which the orbital is located.
For l = 0, n = 1
To find the maximum number of electrons, we use 2n². Where n is 1 for the given problem.
2) In a principle energy level for which n = 3, the maximum number of electrons that can be accommodated is _18__.
We simply evaluate using 2n², since n = 3, the maxium number of electrons would be 2(3)² = 18 electrons
3) Give the appropriate values of n and l for an orbital of 3p: n = _3__, and l = _1__.
3p denotes the principal quantum number(n) and the azimuthal quantum number(l)
n = 3
l = 1
An atom with principal quantum number of 3 will have azimuthal numbers of 0,1 and 2. This shows that six electrons can fill the three degenerate orbitals.
The orbital designation is given as:
for 0 3s
1 3p
2 3d
This is why the 3p orbital will have an azimuthal number of 1.
