Answer:
1.15 molecules
Explanation:
To get to molecules, you need to first convert grams into moles, then moles into molecules.
345g of water x [tex]\frac{1 mol }{18.02g}[/tex]
This will get you the moles of water. (The number 18.02 came form the molar mass of water which is H2O)
I MOLE EQUALS AVOGADRO'S NUMBER
19.15 mol of water x[tex]\frac{6.022*10^{23}molecules }{1 mol}[/tex]
= 1.15
Answer:
There are [tex]1.1542\times 10^{25} [/tex] molecules of water are in 345 grams.
Explanation:
[tex]n=\frac{m}{M}[/tex]
[tex]N=n\times N_A[/tex]
Where:
m = mass of compound
M = Molar mass of compound
N = Number of particles / atoms/ molecules
n = Number of moles
[tex]N_A=6.022\times 10^{23} mol^{-1}[/tex] = Avogadro's number
Mass of water = m = 345 g
Molar mas of water = M = 18 g/mol
[tex]n=\frac{345 g}{18 g/mol}=19.167 mol[/tex]
Number of molecules of water = N
[tex]N=19.167 mol\times 6.022\times 10^{23}mol^{-1}[/tex]
[tex]N = 1.1542\times 10^{25} molecules[/tex]
There are [tex]1.1542\times 10^{25} [/tex] molecules of water are in 345 grams.
