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How much potassium chlorate (KCIO3) must decompose in order to produce 150 grams of oxygen gas (O2)?
Potassium chlorate decomposes according to the following balanced equation:
2KCIO3 + heat → 2KCI+ 3O2​

Respuesta :

Answer:

765.95 grams.

Explanation:

2 moles of KClO3 produce 3 moles of oxygen.

Using molar masses:

2 * 122.545 g of KCLO3  produces 47.997 grams of oxygen.

47.997 g O2 is produced from 245.09 g KCLO3

150 g    ..........................................    150 * 245.09 / 47.997

= 765.95 grams.

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