For this case we have by definition, that the area of a square is given by:
[tex]A = l ^ 2[/tex]
While the perimeter is given by:
[tex]p = 4l[/tex]
Where:
l: It's the side of the square.
Square 1: [tex]l = 2.5[/tex]
[tex]A = (2.5) ^ 2 = 2.5 * 2.5 = 6.25\\p = 4 (2.5) = 10[/tex]
Square 2: [tex]l = 5[/tex]
[tex]A = (5) ^ 2 = 5 * 5 = 25\\p = 4 (5) = 20[/tex]
We can see that the perimeter of the second square is double that of the first. In addition, the second area is four times that of the first square.
Answer:
[tex]p_ {2} = 2p_ {1}\\A_{2} = 4A_ {1}[/tex]
