Respuesta :
Answer:
slope = - [tex]\frac{1}{2}[/tex]
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = 2x + 5 is in this form with slope m = 2
Given a line with slope m then the slope of a line perpendicular to it is
[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{2}[/tex]
Answer:
Slope [tex]m_{2} = \frac{-1}{2}[/tex].
Step-by-step explanation:
Given : equation is y = 2x+5.
To find : What is the slope of a line perpendicular to the line.
Solution : We have given y = 2x+5.
On comparing by the slope form of line is
y = mx + b
where, m = slope , b = y-inercept.
So , [tex]m_{1}[/tex] = 2 .
When the two line are perpendicular to each other then thier slope is
[tex]m_{2} = \frac{-1}{m_{1}}[/tex].
Then plug the value of [tex]m_{1}[/tex] = 2 .
[tex]m_{2} = \frac{-1}{2}[/tex].
[tex]m_{2} = \frac{-1}{2} [/tex].
Therefore, Slope [tex]m_{2} = \frac{-1}{2}[/tex].
