Use the following equation to help you answer the question. The peak intensity of radiation from a star named Sigma is 2 x 10 6 nm. What is the average surface temperature of Sigma rounded to the nearest whole number

Respuesta :

Answer:

1449 K

Explanation:

The surface temperature of a star is related to its peak wavelength by Wien's displacement law:

[tex]T=\frac{b}{\lambda}[/tex]

where

T is the surface temperature

b is Wien's displacement constant

[tex]\lambda=2\cdot 10^{-6} m [/tex]

So the surface temperature of the star is

[tex]T=\frac{2.898 \cdot 10^{-3} Km}{2\cdot 10^{-6} m}=1449 K[/tex]

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