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if measurements of a gas are 75N 300 kPa and then the gas is measured a hey second time and found to be 50 L, describe what had happen to the pressure include which law supports this observation

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machmorgan88

Answer:

P₁V₁ = P₂V₂

300*75 = P₂*50

P₂*50= 300*75

P₂ = 300*75/50 = 450

P₂ = 450 kiloPascals.

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