Answer:
The power dissipated is quadrupled
Explanation:
The power dissipated by a circuit is given by
[tex]P=I^2 R[/tex]
where
I is the current
R is the resistance
In this problem, the resistance is kept constant, while the current is doubled:
I' = 2I
So, the new power dissipated is
[tex]P'=I'^2 R = (2I)^2 R= 4I^2 R=4P[/tex]
So, the power dissipated is quadrupled.