Respuesta :

bearing in mind that the average rate of change = slope, and for that we can simply use two points off the table.

[tex]\bf \begin{array}{|cc|ll} \cline{1-2} x&y\\ \cline{1-2} -2&12\\ 0&3\\ 3&-10.5\\ 7&-28.5\\ \cline{1-2} \end{array}\qquad \qquad \begin{array}{llll} (\stackrel{x_1}{-2}~,~\stackrel{y_1}{12})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{-10.5}) \\\\\\ slope \implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-10.5-12}{3-(-2)} \\\\\\ \cfrac{-10.5-12}{3+2}\implies \cfrac{-22.5}{5}\implies -\cfrac{4.5}{1}\implies -4.5 \end{array}[/tex]

The rate of change of y with respect to x for the given function with coordinates expressed in the table is; dy/dx = -9/2

The rate of change of y with respect to x for a given linear function is simply the slope expressed as;

dy/dx = (y2 - y1)/(x2 - x1)

Let us take the first 2 coordinates which are;

(-2, 12) and (0, 3)

Thus;

dy/dx = (3 - 12)/(0 - (-2))

dy/dx = -9/2

Or dy/dx = -4.5

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