The officer stepped off 20 paces from E to G. If his pace is 2 1/2 feet long. How wide was the river?
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Answer:
The wide of river is [tex]50\ ft[/tex]
Step-by-step explanation:
In this problem we know that
Triangles DEG and DEF are congruent by ASA (Angle-Side-Angle) Congruence
therefore
EG=EF
[tex]EG=20*(2\frac{1}{2})=20*\frac{5}{2}=50\ ft[/tex]