ANSWER
[tex]w = 50.5[/tex]
[tex]l = 88.5[/tex]
EXPLANATION
The basketball court has a rectangular shape.
The perimeter of this court is calculated using the formula
[tex]P=2(l + w)[/tex]
It is given that,the court has a perimeter of 278ft. Let the width of the court be 'w' units, then the length is "w+38"
The perimeter then becomes:
[tex]2(w + 38+ w) = 278[/tex]
[tex]2w + 38= 139[/tex]
[tex]2w = 139 - 38[/tex]
[tex]2w = 101[/tex]
[tex]w = 50.5[/tex]
[tex]l = 50.5 + 38 = 88.5[/tex]
Check
[tex]P = 2(88.5 + 50.5)[/tex]
[tex]P = 2(139) = 278[/tex]
