According to Boyle's law, what would happen to the temperature of a gas if the pressure were halved as the number of moles and the volume were held constant?

A.The temperature would double.
B.The temperature would be reduced by half.
C.The temperature would quadruple.
D.The temperature would be one-quarter of its original value.

Respuesta :

The answer would be B. The temperature would be reduced by half.

When volume is constant, as pressure increases temperature also increases and the ratio of p/t is constant.

Hope this helps:)

According to Boyle's law, the temperature would double of a gas if the pressure were halved as the number of moles and the volume were held constant. Hence, option A is correct.

What is Boyle's law?

Boyle's law states that at constant temperature, the pressure exerted by a gas is inversely proportional to the volume occupied by it.

If temperature is held constant, the equation is reduced to Boyle's law. Therefore, if you decrease the pressure  (P↓) of a fixed amount of gas, its volume (v ↑) will increase.

(P↓) →  (v ↑)

P∝ [tex]\frac{1}{V}[/tex]

However, if you were to maintain a constant volume while decreasing pressure, the temperature would also have to decrease.

Thus, according to Boyle's law, the temperature would double of a gas if the pressure were halved as the number of moles and the volume were held constant.

Hence, option A is correct.

Learn more about the Boyle's law here:

https://brainly.com/question/24345272

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