Answer:
There are approximately d. 0.595 mol of ZnCl₂ in 3.58×10²³ formula units.
Explanation:
Consider the Avogadro's Constant [tex]N_A[/tex] or equivalently, [tex]L[/tex]:
[tex]N_A \approx \rm 6.02\times 10^{23}\;mol^{-1}[/tex].
In other words, there are [tex]\rm 6.02\times 10^{23}\;mol^{-1}[/tex] constituent particles (Wikipedia) in each mole of a substance. In this case,
- Zinc chloride [tex]\rm ZnCl_2[/tex] is the substance, and
- [tex]\rm ZnCl_2[/tex] formula units are the constituents.
[tex]N = 3.58\times 10^{23}[/tex].
[tex]\displaystyle n = \frac{N}{N_A} =\rm \frac{3.58\times 10^{23}}{6.02\times 10^{23}\;mol^{-1}} = 0.595\;mol[/tex].
