If we divide both sides by -2, we have
[tex]bx-5 = -8 \iff bx = -3 \iff x = -\dfrac{3}{b}[/tex]
So, if you choose b=3, you have x = -3/3=-1
a)
The value of x in terms of b is:
[tex]x=\dfrac{-3}{b}[/tex]
b)
The value of x when b is 3 is:
[tex]x=-1[/tex]
We are given a equation in terms of x and b as follows:
[tex]-2(bx-5)=16-----------(1)[/tex]
a)
Now on simplifying the equation i.e. we solve for x i.e. we find the value of x in terms of b as follows:
On dividing both side of the equation by -2 we get:
[tex]bx-5=-8[/tex]
Now on adding both side by 5 we get:
[tex]bx=-8+5\\\\\\bx=-3[/tex]
Now, on dividing both side of the equation by b we get:
[tex]x=\dfrac{-3}{b}------------(2)[/tex]
b)
when b=3 in equation (2) we have:
[tex]x=\dfrac{-3}{3}\\\\\\x=-1[/tex]
