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A species of fly has two alleles for the length of their legs. The allele for long
legs is dominant, and is represented by p. The allele for short legs is
recessive, and is represented by q. If 21 of 100 organisms have short legs,
what is p?
p'+ 2pq + q* = 1
O A. 0.54
OB. 0.21
O C. 0.79
O D. 0.46

Respuesta :

The answer is A. 0.54.

In a population p+q=1 (we have 2 alleles only).

The question states that 0.21 of the population(21%) have short legs meaning they are q^2.

So q=rad0.21=0.4582.

And p=1-q=0.5417.
luisvaschetto

If 21 of 100 organisms have short legs (q2 = 0.21 >> q = 0.46), then the value of p is equal to 0.54.

What is the Hardy-Weinberg equilibrium?

Hardy-Weinberg equilibrium is a model used in population genetics to estimate genetic and allele frequencies.

  • This model (Hardy-Weinberg equilibrium) is used to estimate allele frequencies in absence of different evolutionary forces.

In conclusion, if 21 of 100 organisms have short legs (q2 = 0.21 >> q = 0.46), then the value of p is equal to 0.54.

Learn more about the Hardy-Weinberg equilibrium here:

https://brainly.com/question/3406634

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