Answer:
Step-by-step explanation:
In this problem the "critical points" are the x-intercepts. Find these by setting x^2 + 12x + 35 = to 0 and solving for x. The coefficients of this quadratic are a = 1, b = 12 and c = 35, and so the discriminant is b^2-4(a)(c) = 144-4(1)(35), or 4.
Thus, the roots (x-intercepts) are:
-12 ± √4 -12 ± 2 -6 ± 1
x = --------------- = --------------- = -------------- = -5 and -7.
The intervals in question are thus (-infinity, -7), (-7, -5), (5, infinity). Possible test points (one from each interval) are { -10, -6, 10}
2(1) 2 1
