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NEED HELP ASAP!! Will give brainliest!
What is the equation of the line that is parallel to y-3x=2 and that passes through (6,1)?
y=3x-17
y=3x+19
y=-3x+19
y=-3x-17

NEED HELP ASAP Will give brainliest What is the equation of the line that is parallel to y3x2 and that passes through 61 y3x17 y3x19 y3x19 y3x17 class=

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kudzordzifrancis

ANSWER

[tex]y = 3x - 17[/tex]

EXPLANATION

The given line has equation;

[tex]y - 3x = 2[/tex]

We solve for y to get;

[tex]y = 3x + 2[/tex]

The slope of this line is 3.

Since tyheline is parallel to this line, it also has slope 3.

The line passes through (6,1), we can use the slope intercept form,

[tex]y-y_1=m(x-x_1)[/tex]

We substitute the point and the slope to get;

[tex]y - 1 = 3(x - 6)[/tex]

[tex]y = 3x - 18 + 1[/tex]

[tex]y = 3x - 17[/tex]

luisejr77

Answer: First Option

[tex]y = 3x - 17[/tex]

Step-by-step explanation:

For a linear equation of the form

[tex]y = mx + b[/tex] the slope of the line is the constant m.

In this case we have the line

[tex]y-3x=2\\y=3x +2[/tex]

Then the slope is [tex]m=3[/tex]

If the equation of the line sought is parallel to the line [tex]y=3x +2[/tex] then by definition both lines have the same slope m = 3

Therefore the equation of the line sought is:

[tex]y = 3x + b[/tex]

Where b is a constant that represents the intersection of the line with the y axis.

[tex]b = y_0 -3(x_0)[/tex]

Where [tex](x_0, y_0)[/tex] is a point belonging to the line sought.

In this case the point is (6, 1)

So

[tex]b =1 -3(6)[/tex]

[tex]b =-17[/tex]

Finally the equation is:

[tex]y = 3x - 17[/tex]

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