Respuesta :
Answer:
3 - [tex]\sqrt{11}[/tex]
Step-by-step explanation:
Radical roots occur in conjugate pairs.
3 + [tex]\sqrt{11}[/tex] is a root then so is 3 - [tex]\sqrt{11}[/tex]
Answer:
[tex]3-\sqrt{11}[/tex]
Step-by-step explanation:
The function [tex]f(x)[/tex] has a grade of 4, becaus it has 4 roots.
Now, if one of its roots is [tex]3+\sqrt{11}[/tex], it means there fourth is [tex]3-\sqrt{11}[/tex], because square roots have two results, one positive and one negative.
So, the function cannot have a positive square root solution and not have a negative root solution.
Therefore, the right answer is [tex]3-\sqrt{11}[/tex].
