y= x + 2 and y = x^2 - 4
Substitute mx + b for y
x^2 - 4 = x + 2
Solve for x
x^2 - 4 = x + 2
x^2 - x - 6 = 0
(x - 3)(x + 2) = 0
x - 3 = 0; x = 3
x + 2 = 0; x = -2
Substitute the first x value into the linear equation and solve for y
y = 3 + 2
y = 5
One solution is (3, 5)
Substitute the second x value into the linear equation and solve for y
y = -2 + 2
y = 0
Another solution is (-2 , 0)
