For this case we must simplify the following expression:
[tex]\frac {\frac {4t ^ 2-16} {8}} {\frac {t-2} {6}} =[/tex]
Applying double C we have:
[tex]\frac {6 (4t ^ 2-16)} {8 (t-2)} =[/tex]
Simplifying:
[tex]\frac {3 (4t ^ 2-16)} {4 (t-2)} =[/tex]
We take common factor 4 from the parentheses of the numerator:
[tex]\frac {3 * 4 (t ^ 2-4)} {4 (t-2)} =[/tex]
We simplify:
[tex]\frac {3 (t ^ 2-4)} {(t-2)} =[/tex]
We factor the numerator:
[tex]t ^ 2-4 = (t + 2) (t-2)[/tex]
We rewrite the expression:
[tex]\frac {3 (t + 2) (t-2)} {(t-2)} =[/tex]
We simplify:
[tex]3 (t + 2) =\\3t + 6[/tex]
Answer:
[tex]3t + 6[/tex]
