Answer:
762.55 g.
Explanation:
- For the balanced reaction:
3Cu + 8HNO₃ → 3Cu(NO₃)₂ + 2NO + 4H₂O.
It is clear that 3 mol of Cu reacts with 8 mol of HNO₃ to produce 3 mol of Cu(NO₃)₂, 2 mol of NO, and 4 mol of H₂O.
- We need to calculate the no. of moles of copper consumed when 16.0 moles of water are produced:
Using cross multiplication:
3 mol of Cu produce → 4 mol of H₂O, from stichiometry.
??? mol of Cu produce → 16 mol of H₂O.
∴ no. of moles of Cu needed = (3 mol)(16 mol)/(4 mol) = 12 mol.
- Now, we can get the mass of Cu needed:
∴ mass of Cu = (no. of moles)(atomic mass of Cu) = (12 mol)(63.546 g/mol) = 762.55 g.
