At a busy street corner, one of every hundred jaywalkers will be hit when they cross. What is the probability of a jaywalker not being hit if he makes a round trip daily for thirty days? (0.01)30 (0.99)30 (0.9801)30

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Answer: Last option

[tex]p = (0.9801) ^ {30}[/tex]

Step-by-step explanation:

the probability of a jaywalker being hit is

[tex]P = \frac{1}{100} = 0.01[/tex].

So the probability of a jaywalker not being hit is:

[tex]P '= 1-0.01[/tex]

[tex]P '= 0.99[/tex]

As in this experiment the probability of each trial is independent then, the probability that it is not a jaywalker will not be hit if it makes a round trip is:

[tex]P '= (0.99) (0.99) = 0.9801[/tex]

[tex]P '= 0.9801[/tex]

If this experiment is repeated for 30 days then the probability that it is not a jaywalker will not be hit if it makes a round trip is:

[tex]p = (0.9801) ^ {30}[/tex]

Answer:

(0.9801) 30

Step-by-step explanation: