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A cable exerts a constant upward tension of magnitude 2.14 ✕ 104 N on a 1.80 ✕ 103 kg elevator as it rises through a vertical distance of 2.30 m. HINT (a) Find the work done by the tension force on the elevator (in J)

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skyluke89

Answer:

49220 J

Explanation:

The work done by the tension force on the elevator is given by:

W = F d

where

F is the magnitude of the tension

d is the vertical distance through which the elevator has moved

Here we have

[tex]F=2.14\cdot 10^4 N[/tex]

d = 2.30 m

Substituting,

[tex]W=(2.14\cdot 10^4 N)(2.30 m)=49220 J[/tex]

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